+- Forums (https://eu-forums.com)
+-- Forum: World Wide Talk (https://eu-forums.com/forum-12.html)
+--- Forum: Science and Technology Forum (https://eu-forums.com/forum-8.html)
+--- Thread: CHemIStRY!!? (/thread-5497.html)
CHemIStRY!!? - Angbor - 01-25-2011
what mass of NaOH should be added to 300.0ml of water in order to prepare a solution with a pH=11.50?
Re: CHemIStRY!!? - ElmerCSmith - 01-25-2011
If pH = 11.50 then pOH = 14-11.5 = 2.50
[OH-] = 10 raised to the -2.5 power
[OH-] = 0.00316 mol/L
0.3 L x (0.00316 mol/L) x (40 g/mol) = 0.0379 g NaOH