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Angbor · 01-25-2011, 01:54 PM

what mass of NaOH should be added to 300.0ml of water in order to prepare a solution with a pH=11.50?

ElmerCSmith · 01-25-2011, 01:56 PM

If pH = 11.50 then pOH = 14-11.5 = 2.50

[OH-] = 10 raised to the -2.5 power

[OH-] = 0.00316 mol/L

0.3 L x (0.00316 mol/L) x (40 g/mol) = 0.0379 g NaOH

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